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1x^2-121x+43=0
We add all the numbers together, and all the variables
x^2-121x+43=0
a = 1; b = -121; c = +43;
Δ = b2-4ac
Δ = -1212-4·1·43
Δ = 14469
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-121)-\sqrt{14469}}{2*1}=\frac{121-\sqrt{14469}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-121)+\sqrt{14469}}{2*1}=\frac{121+\sqrt{14469}}{2} $
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